20 Sep
2010
20 Sep
'10
8:44 a.m.
On Sat, Sep 18, 2010 at 12:04 PM, [Ricardo Rodriguez] eBioTIC.
<ricardo.rodriguez(a)ebiotic.net> wrote:
Hi!
Caleb James DeLisle wrote:
$context.getUser() returns a String representing the full name of the
current user document (ex: "XWiki.RicardoRodriguez").
This is why, all the String methods can be applied on the returned value.
There are various ways with different levels of
code cleanliness
since all user names start off with 'XWiki.' you could use
$context.getUser().substring(6)
If you're looking for the user's "common name" instead of the user
name, you might want to look at
$xwiki.getUserName
http://maven.xwiki.org/site/xwiki-core-parent/xwiki-core/apidocs/com/xpn/xw…
Please, as $context is a class and getUser() is a method of that class,
what is .substring()?
Let's call *name* to the answer to the previous question. Please, where
are the possible *name* that could be used with a given method of a
given class?
I'm browsing XWiki API looking for a way of doing the same you have
proposed with .getUser() but with the name of a document. That is, how
to get Document instead Space.Document.
For instance, here...
#set($results=$xwiki.searchDocuments($query))
#foreach($item in $results)
#set ($itemdoc = $xwiki.getDocument($item))
* [$itemdoc>$itemdoc], ~~$itemdoc.display('Genrus')
$itemdoc.display('Species')~~<br/>
$itemdoc shows Space.Document. How do I get just Document?
You have to get the name of the document:
$itemdoc.name
Raluca.
Please, excuse me if this questions are too basic! Thanks for your help!
--
Ricardo Rodríguez
CTO
eBioTIC.
Life Sciences, Data Modeling and Information Management Systems
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users