Re: [xwiki-users] How to filter livetable

Hello, I installed xwiki a few days ago and I'm still learning the ropes. I created a new class called VersionInformation with its associated template and sheet. I'm able to create objects and display them in a livetable, but I have a hard time using the queryFilters option. My class has a Version field which I'd like to filter on. Here is my code: {{velocity}} #set($columns = ["Name", "CoreTag", "ReleaseDate"]) #set($columnsProperties = { "Name": { "link" : "none" } }) #set($options = { "className":"Development.Resources.Version Information.VersionInformationClass", "tagCloud" : true, "rowCount": 20, "queryFilters" : $4_0QueryFilter }) #livetable("4_0_VersionInformation" $columns $columnsProperties $options) {{/velocity}} I have no clue as to how the 4_0QueryFilter variable should be created. I'm guessing something along the lines of #set($4_0_QueryFilter = $services.query.xwql("Version='4.0'") ) but that doesn't work. I tried other variations on that with a WHERE statement, with the .execute() and so on but no success so far. Can somebody help me out on this? Thanks Phil -- View this message in context: http://xwiki.475771.n2.nabble.com/How-to-filter-livetable-tp7598115.html Sent from the XWiki- Users mailing list archive at Nabble.com. _______________________________________________ users mailing list users(a)xwiki.org http://lists.xwiki.org/mailman/listinfo/users