[xwiki-devs] Using XInclude for parsing XAR documents?
Hello fellow developers, in order for the current source file to be a real source file outside of the XML of the xar, e.g. a .properties, a .vm, a .groovy, it would be enough to enable XInclude on the parser that reads the XML document. Which source should I look into? Also, where for xwiki 1.5? thanks in advance paul
There is a tool in the sandbox which can take any xml file and unpack it into a directory tree. If run on an xwiki xml file from the .xar, this tree will have a file in it called content which will contain all of the content of the document. Not sure if that's what you are looking for but it's there. http://svn.xwiki.org/svnroot/xwiki/contrib/sandbox/xwiki-dirtree/ Caleb On 11/15/2010 11:44 AM, Paul Libbrecht wrote:
Hello fellow developers,
in order for the current source file to be a real source file outside of the XML of the xar, e.g. a .properties, a .vm, a .groovy, it would be enough to enable XInclude on the parser that reads the XML document.
Which source should I look into? Also, where for xwiki 1.5?
thanks in advance
paul _______________________________________________ devs mailing list [email protected] http://lists.xwiki.org/mailman/listinfo/devs
On Mon, Nov 15, 2010 at 17:44, Paul Libbrecht <[email protected]> wrote:
Hello fellow developers,
in order for the current source file to be a real source file outside of the XML of the xar, e.g. a .properties, a .vm, a .groovy, it would be enough to enable XInclude on the parser that reads the XML document.
Which source should I look into? Also, where for xwiki 1.5?
thanks in advance
You can find the maven xar plugin on http://svn.xwiki.org/svnroot/xwiki/platform/xwiki-tools/trunk/xwiki-xar-plug...
paul _______________________________________________ devs mailing list [email protected] http://lists.xwiki.org/mailman/listinfo/devs
-- Thomas Mortagne
participants (3)
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Caleb James DeLisle -
Paul Libbrecht -
Thomas Mortagne