Hi, On Jan 16, 2009, at 4:05 PM, Kevin_C wrote:

Why can't I do something like:

#set($tRule = "") #set($idx = $tRule.indexOf(','))

$idx ## Outputs -1

$idx+1 ## Outputs -1+1

I've tried using the $number tool but it doesn't work, if I do:

$number.format($idx)

It outputs $number.format($idx).

See http://platform.xwiki.org/xwiki/bin/view/DevGuide/Scripting (it's $numbertool)

What am I missing?

.:. Kevin

Thanks -Vincent http://xwiki.com http://xwiki.org http://massol.net

Yah, that makes sense.. Still trying to get the hang of all this. Thanks again!! .:. Kevin -- View this message in context: http://n2.nabble.com/Strangeness-with-numbers...-tp2168613p2170342.html Sent from the XWiki- Users mailing list archive at Nabble.com.

On Jan 16, 2009, at 9:03 PM, Kevin_C wrote:

Ugh, typo. Sorry. I ended up using $util.add($num, 1)..

Don't use that one it's deprecated and will be removed soon. Look at your logs you should see the deprecation warning appearing. Use numbertool instead. Thanks -Vincent http://xwiki.com http://xwiki.org http://massol.net

nm, I found $mathtool which allows addition of 2 objects. Thanks! .:. Kevin Kevin_C wrote:

OK, then how do I add two numbers using the numbertool? Here's what I have:

$numbertool.toNumber($tRule.indexOf('.'))

This displays a number as a string just fine. Now, I need to add 1 to it. I've tried:

$numbertool.toNumber($tRule.indexOf('.')).intValue()+1 ## displays 1+1

$numbertool.toNumber($tRule.indexOf('.')+1) ## crashes

$numbertool.format($numbertool.toNumber($tRule.indexOf('.')).intValue()+1) ## crashes

$numbertool.toNumber($numbertool.toNumber($tRule.indexOf('.'))+1) ## crashes

I know this is a scripting language and all but it doesn't seem that something this simple should be so hard to do. Does velocity not have the concept of a number?!?

Thanks! .:. Kevin

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