On 09/28/2011 05:20 PM, Legeinfo wrote:

I want to split a dato string like 2011.08.02 into year, month and days to calculate the age of a person. $year = 2011 $month = 08 $day = 02

$year =($date.replaceAll($'\d\d\d\d.','$1')) is not working.

I'm not sure what you tried to write there, but it doesn't look right. There are many ways to do this. When you said "split", the most straight-forward way to do this seems to be: #set ($date = "2011.08.02") #set ($datePieces = $date.split('\.')) $datePieces[0] $datePieces[1] $datePieces[2] If you really want a solution based on replaceAll, then this seems to work: #set ($date = "2011.08.02") #set ($year = $date.replaceAll('(\d{4})\..*', '$1')) #set ($month = $date.replaceAll('\d{4}\.(\d{1,2})\..*', '$1')) #set ($day = $date.replaceAll('.*\.(\d{2})$', '$1')) $year $month $day The most flexible way would be to use the jodatime plugin to parse this string into a real DateTime object, from which you can request the various date parts explicitly. #set ($date = "2011.08.02") #set ($dateObj = $xwiki.jodatime.getDateTimeFormatterForPattern('yyyy.MM.dd').parseDateTime($date)) $dateObj.year $dateObj.monthOfYear $dateObj.dayOfMonth -- Sergiu Dumitriu http://purl.org/net/sergiu/