Hosam Hassan wrote:
Hello Sergiu,
The $doc.displayTitle still removes the spaces from the title. As for the
$doc.name.replaceAll('([a-z])([A-Z])', '$1 $2')
I get that exception when I execute it
That's a problem with the current backlink gathering mechanism. Try using: $doc.name.replaceAll('([a-z])([AB-Z])', '$1 $2')
Original Message:
Hosam Hassan wrote: <br />> Yes I know this already but for example if u want to create a new page called <br />> <br />> World cup <br />> <br />> The page will be called worldcup <br />> <br />> if u do a [$doc.name] Here the name of the link will be normal "World Cup" <br />> <br />> BUT if u do a $doc.name u will get worldcup. <br />> <br />> My problem is i want to get the normal name of the page which is displayed when u do a [$doc.name] <br />> <br /> <br />That is not the document name, but the document title. You can get it <br />with $doc.displayTitle <br /> <br />If you want to camelcase the document name, you can use: <br />
-- Sergiu Dumitriu http://purl.org/net/sergiu/