Re: [xwiki-users] XML with getURLContent()

Seems to be working fine on http://playground.xwiki.org/xwiki/bin/view/Main/Aaron Maybe there was a problem specifically on 6.2RC1 (BTW better use some final releases…:)). I’d recommend 6.4.5 for the 6.x cycle. Thanks -Vincent On 15 Sep 2015 at 18:53:16, Aaron Hardy at AC (ashtarcommunications(a)gmail.com) wrote: Page syntax is XWiki 2.1 and the velocity is wrapped. Sorry, I didn't include the full code for simplicity's sake. Here's a minimal example cut and pasted from the editor (only thing changed is the actual URL): ******************************* {{velocity}}   #set($getURL = "https://www.example.com/api/example.mhtml?param=123")   $getURL   #set($content = $xwiki.getURLContent($getURL))   $content {{/velocity}} If I set $getURL to "https://google.com", it prints $content to the page. With my API URL, I get nothing but the link in $getURL. But if I follow that link, I get the expected XML page from the API, so I know the URL is working correctly. I figured it was because $content is XML from the API, and HTML from google, but using $services.xml.parse on the response doesn't work either. The strange part is that this is code that I haven't touched in quite some time, and used to be working. The full code parses the XML response and saves various elements to an HTML table on the page - but it doesn't appear to be getting that far. On Tue, Sep 15, 2015 at 12:41 PM, vincent(a)massol.net <vincent(a)massol.net> wrote: Hi Aaron, On 15 Sep 2015 at 18:38:17, Aaron Hardy at AC (ashtarcommunications@gmail.com(mailto:ashtarcommunications@gmail.com)) wrote: What is the syntax of your page? Are you sure it’s XWiki Syntax 2.0+ and you’re wrapping the velocity content with the {{velocity}} macro for example (you didn’t show it in your example).  $response is still there Thanks -Vincent