11 Sep
2010
11 Sep
'10
2:49 p.m.
[Ricardo Rodriguez] eBioTIC. wrote:
Hi!
Caleb James DeLisle wrote:
Another way of writing is:
#set($nameString = $xcontext.getUser())
#set($nameStringWithNoPrefix = $nameString.substring(6))
substring is a function of java.lang.String which is what's returned by
context.getUser()
You can google java.lang.String to get a listing of all of String's functions.
There are various ways with different levels of
code cleanliness
since all user names start off with 'XWiki.' you could use
$context.getUser().substring(6)
If you're looking for the user's "common name" instead of the user
name, you might want to look at
$xwiki.getUserName
http://maven.xwiki.org/site/xwiki-core-parent/xwiki-core/apidocs/com/xpn/xw…
Please, as $context is a class and getUser() is a method of that class,
what is .substring()?
Let's call *name* to the answer to the previous question. Please, where
are the possible *name* that could be used with a given method of a
given class?
I'm browsing XWiki API looking for a way of doing the same you have
proposed with .getUser() but with the name of a document. That is, how
to get Document instead Space.Document.
For instance, here...
#set($results=$xwiki.searchDocuments($query))
#foreach($item in $results)
#set ($itemdoc = $xwiki.getDocument($item))
* [$itemdoc>$itemdoc], ~~$itemdoc.display('Genrus')
$itemdoc.display('Species')~~<br/>
$itemdoc shows Space.Document. How do I get just Document?
Please, excuse me if this questions are too basic! Thanks for your help!
If you just put the name of the document ie:
* [$itemdoc]
It should extract the user friendly name and display it automatically.
BTW: That is syntax/1.0 and all new development on the rendering engine is for the
syntax/2.0
renderer. 1.0 will not be removed for quite some time but if you want to take advantage of
new
features, I recommend writing new code in syntax/2.0.
Caleb