3 Jun
2014
3 Jun
'14
10:23 a.m.
Hi,
I am trying to decode only once and I'm getting the exception already.
String decodedspacename = URLDecoder.decode(space, "UTF-8").getpath();
Am 03.06.2014 09:50 schrieb "Clemens Klein-Robbenhaar" <
c.robbenhaar(a)espresto.com>gt;:
On 06/03/2014 05:16 AM, Daniel Ebanja wrote:
Hi,
i am receiveing the following exception:
Caused by: java.lang.IllegalArgumentException: URLDecoder: Illegal hex
characters in escape (%) pattern - For input string: "!<"
Hm, are you sure it is already decoded?
I can reproduce the error message you get by decoding it twice ...
My scenario:
Users can create space by using a URL that looks like:
mydomain.com/xwiki/bin/...?space=
%C3%A4%C3%B6%C3%BC%C3%9F%C2%A7%25%21%3C%3E_helloworld
i then try to decode this spacename and create the space without success.
String decodedspacename = URLDecoder.decode(space, "UTF-8");
How should i deal with this?
thanks for your help in advance.
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