Jeroen,
On 3/16/2010 11:34 AM, Jeroen Baten wrote:
Yes, but what if you want to link to an existing
attachment on another
page and you don't know the title of that other page.
So:
1-ask system list of all attachments with pages where there exist
You mean searching all pages containing attachments or a certain
attachment? You could try the search method, though I'm not sure it
supports all hql queries. The xml result will be quite big on a large wiki.
If not, there's always the force brute way: getSpaces -> getPages ->
getAttachments
2-link to attachment on other page.
I'm not sure I understand your use case. The url is still the same if
you don't want to translate it into a xwiki syntax url.
Willing to contribute when I know what to write :-)
any thoughts on why getPageHistory exists in java class but doesn't work
in python? Or is xwiki intelligent enough to prevent calls to yet
undocumented classes? :-)
Not sure why the call fails. We need more details on this.
Florin Ciubotaru
kind regards,
On Tue, 2010-03-16 at 11:10 +0200, Florin Ciubotaru wrote:
Hi,
On 3/16/2010 9:38 AM, Jeroen Baten wrote:
Hello,
When I use the XMLRPC interface from Python I can store a lot of pages,
attachments and even convert syntaxes.
But how can I find if some
attachment already exists in the wiki to make a link to that attachment
and not upload the same attachment over and over again?
Add attachment doesn't have the optional check version as storePage
has.
I think the only way to do that right now is to get the list of
attachments of a page before you start the upload.
For that you can use the Attachment[] getAttachments(..) method. The
Attachment map contains an 'url' key.
You can check the xml-rpc api& model at:
-
http://svn.xwiki.org/svnroot/xwiki/platform/core/trunk/xwiki-xmlrpc/xwiki-x…
For a more complete model and documented api please check:
-
http://svn.xwiki.org/svnroot/xwiki/xoffice/trunk/xword/Connectivity/Clients…
We have some missing elements in our xml-rpc documentation on
xwiki.org,
is this something you could contribute?
Thanks,
Florin Ciubotaru
kind regards,
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