Re: [xwiki-users] Access object from other page

Hello all, I just started with xwiki and i've some trouble to access to object from another page. I don't know if what i'm doing is the best way to do it or not. First i'll explain what i would like to do, and after explain which way i've choose to do it. So, i would like to create a "reference" page. I mean in this page create a table with all the datas i need for ex : *PAGE CONFIG :* |IP|HOSTNAME|ROLE 192.168.0.1|ROUTER|WAN 192.168.0.2|FIREWALL|FIREWALL 192.168.0.3|SERVER1|AD/DC 192.168.0.4|SERVER2|DNS1 192.168.0.5|SERVER3|DNS2 .... Then i create differents FAQ pages where i would like to insert info as "connect on DNS1 (ip : 192.168.0.4)".... But if one day, the ip adress or hostname change (for some reason..) i just have to change the data in the page CONFIG and automatically will be changed on all other pages. Like that no need to edit all pages ... So, what i've done... Probably not the best way to do it. I've create a page with class and object + template. It create for each server a new page with all info i need. so i've for example : *PAGE IP : * IP : 192.168.0.1 HOSTNAME : ROUTER ROLE : WAN *PAGE FIREWALL : * IP : 192.168.0.2 HOSTNAME : FIREWALL ROLE : FIREWALL ... for all other page Now, what i'm looking for is on an other page : *PAGE FAQ 1 * access to the object of the page FIREWALL and display the content of the object. I can display the object of the own page but not from another page. Could you help me in this task plz my code : i don't know how refer the object of the specific page

#set($object = $doc.getObject('test.XWikiTestClass'))

$object.display('IP', 'view') $object.display('HOSTNAME', 'view') $object.display('ROLE', 'view') Regards -- View this message in context: http://xwiki.475771.n2.nabble. com/Access-object-from-other-page-tp7601415.html Sent from the XWiki- Users mailing list archive at Nabble.com. _______________________________________________ users mailing list users(a)xwiki.org http://lists.xwiki.org/mailman/listinfo/users