:) Thomas had mailed me this (after I had personally mailed him) in reply to
my question about removing the hyperlink with the pretty-name of the current
user.
----------
In $xwiki you have all theses methods :
getUserName(user)
getUserName(user, link)
getUserName(user, format)
getUserName(user, format, link)
it seam that in getUserName(user) "link" is true by default so it
return you the name with a correct link to access it, if you don't
want the link I suppose $xwiki.getUserName($context.getUser(), false)
is correct.
When you search for api methods the better way is to print the class
and then go to javadoc to see the methods in the class. For example
for $context you can do $context.class that print you the exact JAVA
class and then you go to
http://www.xwiki.org/xwiki/bin/download/DevGuide/API/xwiki%2Dcore%2D1.1.1%2…
and click on Context class link to see all methods $context contains.
-----------
Thomas Mortagne wrote:
If you want a prettier (FirstName LastName) user name you can use
$xwiki.getLocalUserName($context.getUser()).
2007/11/7, Thomas Mortagne <thomas.mortagne(a)xwiki.com>om>:
Hi,
You can get user name with $context.getLocalUser() or users full name
with $context.getUser(). Full name means generally containing "XWiki."
be fore user name, it's the full name of the document containing the
user.
2007/11/7, V. Harikrishnan Nair <harikrishnan_v(a)amritatech.com>om>:
Hi...
I tried use $xwiki.getUser to get the current user's name but I got a
value
like this
'com.xpn.xwiki.api.User@13095c7'.
So, I looked into the API doc and used getLocalUser() but it does not
work.
This is the syntax that I used -
#set($user = $xwiki.getLocalUser())
$user
What is wrong here ? It had given me an output for getUser().
Harikrishnan
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