24 Jun
2014
24 Jun
'14
9:21 p.m.
Hello Sirs,
I need to implement the function "jsontool.serialize" in the code below, groovy,
and I do not understand the error that is accusing, can help me solve this?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def json = ['totalprojetos':
listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
for(item in listProjetos){ def hql = "select distinct list from BaseObject as obj,
DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' "; def tag =
services.query.hql(hql).execute(); i = i + 1;
json.projetos.add({ id: xwiki.getDocument(item).getName() })}
jsontool.serialize(json);
{{/groovy}}
Ty.
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
27 Jun
27 Jun
10:33 a.m.
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them manually in your script, like:
def jsontool = new org.xwiki.velocity.tools.JSONTool()
I feel there should be a better way to do that, but it works this way.
(it is likely that using groovy.json.JsonBuilder() works, too, but I have not tried)
Clemens
On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
Hello Sirs,
I need to implement the function "jsontool.serialize" in the code below,
groovy, and I do not understand the error that is accusing, can help me solve this?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def json = ['totalprojetos':
listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
for(item in listProjetos){ def hql = "select distinct list from BaseObject as obj,
DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' "; def tag =
services.query.hql(hql).execute(); i = i + 1;
json.projetos.add({ id: xwiki.getDocument(item).getName() })}
jsontool.serialize(json);
{{/groovy}}
Ty.
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
11:51 a.m.
You should probably use JsonBuilder which is the standard tool to
manipulate JSON in Groovy.
On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
<c.robbenhaar(a)espresto.com> wrote:
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them manually in your script, like:
def jsontool = new org.xwiki.velocity.tools.JSONTool()
I feel there should be a better way to do that, but it works this way.
(it is likely that using groovy.json.JsonBuilder() works, too, but I have not tried)
Clemens
On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
--
Thomas Mortagne
Hello Sirs,
I need to implement the function "jsontool.serialize" in the code below,
groovy, and I do not understand the error that is accusing, can help me solve this?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def json = ['totalprojetos':
listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
for(item in listProjetos){ def hql = "select distinct list from BaseObject as
obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' "; def tag =
services.query.hql(hql).execute(); i = i + 1;
json.projetos.add({ id: xwiki.getDocument(item).getName() })}
jsontool.serialize(json);
{{/groovy}}
Ty.
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
30 Jun
30 Jun
8:23 p.m.
I'm trying to implement a function that told me but I can not add the data online, I
can only add one. How do I do that?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def i = 0;def data = new groovy.json.JsonBuilder();data
= ["totalprojetos": listProjetos.size(),"projetos": [ id:
"", tag: "", label: "",
size: "", color: "", x: "",
y : "" ],"edges":[ id: "",
source: "", target: "" ]];
for(item in listProjetos){ def hql = "select distinct list from BaseObject as obj,
DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' "; def tag =
services.query.hql(hql).execute(); i = i + 1; data.projetos.id=1;
data.projetos.tag="tags"; data.projetos.label="Label do projeto";
data.projetos.size=5; data.projetos.color="#696969"; data.projetos.x=1;
data.projetos.y= 1;}
def json = new groovy.json.JsonBuilder(data)println json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
Date: Fri, 27 Jun 2014 11:51:47 +0200
From: thomas.mortagne(a)xwiki.com
To: users(a)xwiki.org
Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
You should probably use JsonBuilder which is the standard tool to
manipulate JSON in Groovy.
On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
<c.robbenhaar(a)espresto.com> wrote:
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them manually in your script, like:
def jsontool = new org.xwiki.velocity.tools.JSONTool()
I feel there should be a better way to do that, but it works this way.
(it is likely that using groovy.json.JsonBuilder() works, too, but I have not tried)
Clemens
On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
--
Thomas Mortagne
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users Hello Sirs,
I need to implement the function "jsontool.serialize" in the code below,
groovy, and I do not understand the error that is accusing, can help me solve this?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def json = ['totalprojetos':
listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
for(item in listProjetos){ def hql = "select distinct list from BaseObject as
obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' "; def tag =
services.query.hql(hql).execute(); i = i + 1;
json.projetos.add({ id: xwiki.getDocument(item).getName() })}
jsontool.serialize(json);
{{/groovy}}
Ty.
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
1 Jul
1 Jul
2:55 p.m.
Hi Thomas, I instantiate the jsonbuilder as follows in the example yet returned to
previous error that was not allow adding elements in my "json" method. "Add
()".
I have also realized by placing the method within an array as criuado test
("data.projetos [i]. Id.add ()").
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def i = 0;def data = new groovy.json.JsonBuilder();data
= ["totalprojetos": listProjetos.size(),"projetos": [ id:
"", tag: "", label: "", size: "", color:
"", x: "", y : "" ],"edges":[ id: "",
source: "", target: "" ]];
for(item in listProjetos){ def hql = "select distinct list from BaseObject as obj,
DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' ";def tag =
services.query.hql(hql).execute(); i = i + 1; data.projetos.id.add()=1;
data.projetos.tag.add()="tags"; data.projetos.label.add()="Label do
projeto"; data.projetos.size.add()=5; data.projetos.color.add()="#696969";
data.projetos.x.add()=1; data.projetos.y.add()= 1;}
def json = new groovy.json.JsonBuilder(data)println json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
From: eduardo.abritta(a)outlook.com
To: users(a)xwiki.org
Date: Mon, 30 Jun 2014 15:23:37 -0300
Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
I'm trying to implement a function that told me but I can not add the data online, I
can only add one. How do I do that?
{{groovy}}def hql0 = ", BaseObject as obj
where doc.fullName = obj.name and obj.className = 'E-nova.E-novaClass'";def
listProjetos = services.query.hql(hql0).execute();def i = 0;def data = new
groovy.json.JsonBuilder();data = ["totalprojetos":
listProjetos.size(),"projetos": [ id: "",
tag: "", label: "", size: "",
color: "", x: "", y : ""
],"edges":[ id: "", source:
"", target: "" ]];
for(item in listProjetos){ def hql = "select distinct list from BaseObject as obj,
DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' ";def tag =
services.query.hql(hql).execute(); i = i + 1; data.projetos.id=1;
data.projetos.tag="tags"; data.projetos.label="Label do projeto";
data.projetos.size=5; data.projetos.color="#696969"; data.projetos.x=1;
data.projetos.y= 1;}
def json = new groovy.json.JsonBuilder(data)println json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
Date: Fri, 27 Jun 2014 11:51:47 +0200
From: thomas.mortagne(a)xwiki.com
To: users(a)xwiki.org
Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
You should probably use JsonBuilder which is the standard tool to
manipulate JSON in Groovy.
On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
<c.robbenhaar(a)espresto.com> wrote:
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them manually in your script, like:
def jsontool = new org.xwiki.velocity.tools.JSONTool()
I feel there should be a better way to do that, but it works this way.
(it is likely that using groovy.json.JsonBuilder() works, too, but I have not tried)
Clemens
On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
--
Thomas Mortagne
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users Hello Sirs,
I need to implement the function "jsontool.serialize" in the code below,
groovy, and I do not understand the error that is accusing, can help me solve this?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def json = ['totalprojetos':
listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
for(item in listProjetos){ def hql = "select distinct list from BaseObject as
obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and
prop.id.name='tags' and obj.name ='$item' "; def tag =
services.query.hql(hql).execute(); i = i + 1;
json.projetos.add({ id: xwiki.getDocument(item).getName() })}
jsontool.serialize(json);
{{/groovy}}
Ty.
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abritta(a)outlook.com | cel: (32)8472-9631
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
_______________________________________________
users mailing list
users(a)xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
3827
days inactive
3834
days old
4 comments
3 participants
participants (3)
-
Clemens Klein-Robbenhaar -
Eduardo Abritta -
Thomas Mortagne