Hosam Hassan wrote:
Hello Sergiu,
The $doc.displayTitle still removes the spaces from the title. As for the
$doc.name.replaceAll('([a-z])([A-Z])', '$1 $2')
I get that exception when I execute it
That's a problem with the current backlink gathering mechanism. Try using:
$doc.name.replaceAll('([a-z])([AB-Z])', '$1 $2')
Original Message:
Hosam Hassan wrote:
<br />> Yes I know this already but for example if u want to create a new page
called
<br />>
<br />> World cup
<br />>
<br />> The page will be called worldcup
<br />>
<br />> if u do a [$doc.name] Here the name of the link will be normal
"World Cup"
<br />>
<br />> BUT if u do a $doc.name u will get worldcup.
<br />>
<br />> My problem is i want to get the normal name of the page which is
displayed when u do a [$doc.name]
<br />>
<br />
<br />That is not the document name, but the document title. You can get it
<br />with $doc.displayTitle
<br />
<br />If you want to camelcase the document name, you can use:
<br />
--
Sergiu Dumitriu
http://purl.org/net/sergiu/